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C As we saw before, the genes which are cared by the chromosomes are given by both parents to children. The black, blue, chocolate, cinnamon and fawn colours are the ones we will study today.

The black and the blue are almost in every race. The chocolate and the lilac were first in Siamese and Oriental. These two colours are also now in Birman, Burmese and Persian race. Cinnamon and fawn were brought by Abyssian and Somali but it was introduced by the Siamese and the Oriental during the selection of the Orientals ticked.

These are the basic colours which will be intense or pastel either they are with “D+“ (intense) or a “d“ (diluted).

The genes of the two allelic series above, are placed by decline order of dominate :

 

(the dash next to the known gene replaces the second gene of the pair, when, for this gene, the subject can be heterozygous.)

  •      “B+“ is dominant next to “b”, just one of the parents giving it allows to    the kitten to express it.

  •       “b” is recessive next to “B+”. For the chocolate, the kitten must receive “b” from one of his parents, and either “b” or “bl” from the other.

  •       for a kitten to be cinnamon, his two parents must give him “bl”

  •       the colour will express itself intensely if at least one of the parents gives “D+”.

  •       to obtain a diluted colour, the two parents must give “d” to the kitten.

      As the genes are always by two, and that the presence of just one dominant gene is enough to its expression on the phenotype of the kitten, we will be obliged to put a “-“ next to the gene giving this character if we have no precision concerning the second. When this precision is given, the dash is replaced by the discovered gene. To determine rapidly if a subject is homozygous or heterozygous (pure or unpure) for a given gene, we will have to marry it with a partner expressing the most recessive gene of its series. So, a black cat will be able to be married to a blue one to know if he is carrying dilution.

 

PERSAN  NOIR

Ex 1 :

Marriage of a black cat, pure and of a blue which does not hide the chocolate or the cinnamon.

The black is “B+B+ D+D+”, the blue is “B+B+ DD”. The sexual cells has only the half of the chromosomal stock, the gametes of the black cat will be “B+ D+” , and the ones of the blue “B+ d”. The crossing will give the results we will read in the drawing called “Square of the Punnet”, in the intersections of the vertical and horizontal lines.

      

The result is the black carrier of blue, no kitten is blue , what shoes the of parent is homozygous for “D“. The crossing will have to be done several times, because only one litter won’t give enough kitten.

PERSAN BLEU
PERSAN NOIR

PERSAN BLEU

Exemple 2

Marriage of a black carrier of blue and of a blue, none of them carrying the chocolate or the cinnamon.

Given “B+B+ D+d” and “B+B+ dd”.

The blue has only one kind of gametes : “B+d”, whereas the black which is carrier of blue has got two ones : it gives the following chart :

 

So, the half of black kitten; and the other of blue kitten, it is possible that this result appears only after some litter.

Ex 2 bis :

The crossing of two blue will give only blue kitten if they are homozygous (pures) for “B+“, but will be able to give blue point and lilac, if they are carrier of “b”. In that case the chart only considers “B“, because the two parents are diluted and only give ”d”, that is to say :

  What gives effectively 3 blue points and a lilac

Exercise one :

We can also have the crossing between two black kitten, carrier of chocolate and dilution.

Each parent will have 4 kind of gametes : “B+D+”, “B+d”, “bD+”, “bd”

 So, you have the possibility to have black kitten (9/16), blue kitten (3/16), chocolate kitten (3/16), and lilac (1/16).

PERSAN LILAS

PERSAN CHOCOLAT
 

Exercise 3 :

A breeder buys a black male, to cross them with his blue and lilac females. Out of 10 kitten , he obtains 9 black and 1 lilac. What can we deduce of that ?

 

 

At the beginning the black is written : “B+- D+-”. The crossing shows that it is carrier of chocolate and of dilution, for it has given a lilac kitten. Its formula becomes : “B+ D+d”. We do not know if it is or not carrier of cinnamon. Its race can give an indication, because the cinnamon can’t be found in other races than the Orientals, the Abyssians and the Somalis.

 

  Traduction de

Ségolène COURRIER (F)

6).

PERSAN LILAS

PERSAN NOIR